if the distance between the points (1, 2) & (2, 7) is double ofcthe distance of point (k+4, k) from the origin then value of 8k^2+32k+49 is ...............?
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Answers
Answered by
10
Answer:
2
Step-by-step explanation:
Using distance formula, The distance between points (1,2) & (2,7)
= root of [ (2-1)^2 + (7-2)^2 ]
= root 26.
The distance between (0,0) & (k+4,k) is half of root 26.
(root 26)/2 = root of [ (k+4)^2 + k^2 ]
taking squares both sides,
26/4 = k^2 + 8k + 16 + k^2
2(k^2) + 8k + (38/4) = 0
simplify more, we get
8(k^2) + 32k + 38 =0
we have to find ,
8(k^2) + 32k + 40
= 8(k^2) + 32k + 38 +2
= 0 + 2
= 2
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