Question

if the distance between the points [-1,a] and [5,5] is 10, then find a

Answer 1

Given:

• Points (-1,a) & (5,5)
• Distance between the points is 10 units.

To Find:

• Value of a.

Required Response:

$\sqrt{ {(5 - ( - 1))}^{2} + {(5 - a)}^{2} } = 10\\ \sqrt{ {(5 + 1)}^{2} + {(5)}^{2} + {(a)}^{2} - 2(5)(a)} = 10 \\ {(6)}^{2} + 25 + {a}^{2} - 10a = {(10)}^{2} \\ 36 + 25 + {a}^{2} - 10a = 100 \\ 61 + {a}^{2} - 10a - 100 = 0 \\ {a}^{2} - 10a - 39 = 0 \\ {a}^{2} - 13a + 3a - 39 = 0 \\ a(a - 13) + 3(a - 13) = 0 \\ (a - 13)(a + 3) = 0 \\ a = 13 \: (or) \: - 3$

$\boxed{\sf{Distance\; Between\;Two\;Points = \sqrt{{(x_{2}-x_{1})}^{2}+{(y_{2}-y_{1})}^{2}}}}$

Value of a

• $\longmapsto\;{\red{\bold{13\;\&\;-3}}}$

$\tt{@MrMonarque}$

Hope It Helps You ✌️

Answer 2

Answer:

pdicfngkax come

Grive first the Step you will use to sepdate the variable and then solve the equation x+2=3 3x = 6 2x +4=2