If the distance between the points (2,-2) and (-1,x) is 5.Find one of the value of x
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Hey Friend,
Let,
point A = (2,-2)
point B = (-1,X)
Distance AB = 5 units
Applying distance formula,
AB^2 = (x2 - x1)^2 + (y2 - y1)^2
(5)^2 = (-1 - 2)^2 + (X + 2)^2
25 = 9 + X^2 + 4 + 4X
X^2 + 4X - 12 = 0
X^2 + 6X - 2X - 12 = 0
X(X + 6) -2(X + 6) = 0
(X - 2) (X + 6) = 0
Therefore,
X = 2 or X = -6
Hope it helps!
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