Question

If the distance between the points (2, –3) and (10,



b.Is 10 units, find the value of b

Answer 1

Here is your answer buddy,

The points are (2,-3) and (10,b)
The distance = 10 units.

Now the formula to be used is,
√$(X-X') ^{2} - (Y-Y') ^{2}$

Now,

√$(2-10) ^{2} - (-3-b) ^{2}$ = 10
=> √$(-8) ^{2} - (-3-b) ^{2}$ = 10
=> √{64 - $(-3-b)^{2}$}= 10
=> 64 - (-3-b) = 100 (by squaring both sides)
=> 64 - 3 + b = 100
=> - 3 + b = 100 - 64
=> - 3 + b = 36
=> b = 39 unit

Hope this helps you.
Be Brainly.

Answer 2

Answer:

Distance between two points

(x2−x1)2+(y2−y1)2

(x−3)2+(2−(−6))2=10

(x−3)2+64=10

 Squaring both sides

(x−3)2+64=100

x2−6x−27=0

x2−9x+3x−27=0

x(x−9)+3(x−9)=0

x=−3,9

Taking positive value, x=9units