Question

If the distance between the points (2,-3) and (10,p) is 10 , then value of p is *

3,9

-3,9

3,-9

-3,-9​

Answer 1

Answer:

33

Step-by-step explanation:

d=√(x2-x1)+(y2-y1)

10=√(10-2)^2+(p+3)^2

10=√64+(p+3)^2

by squring on both side

100=64+(p+3)^2

100-64=(p+3)^2

36=(p+3)^2

√36=p+3

6-3=p

3=p

Answer 2

Answer:

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf (Distance)^2=(x_2-x_1)^2+(y_2-y_1)^2\\\\\\:\implies\sf (10)^2=(10-2)^2+(p-(-3))^2\\\\\\:\implies\sf 100 = (8)^2+(p + 3)^2\\\\\\:\implies\sf 100=64 + (p + 3)^2\\\\\\:\implies\sf 100 - 64 = (p + 3)^2\\\\\\:\implies\sf 36 = (p + 3)^2\\\\\\:\implies\sf \sqrt{36} = p + 3\\\\\\:\implies\sf \pm \:6 = p + 3\\\\\\:\implies\sf p = 6 - 3 \quad or, \quad p = - \:6 - 3\\\\\\:\implies\underline{\boxed{\sf p = 3\quad or, \quad - \:9}}$

⠀

$\therefore\:\underline{\textsf{Hence, Required value of p is C) \textbf{3 or - 9}}}.$