Question

if the distance between the points (3, p) and (-1 , 0) is 6 units, then find the value of p.​

Answer 1

Step-by-step explanation:

using didtance formulae:

d=√(y2-y1)^2+(x2-x1)^2

6=√(p-0)^2+(-1-3)^2

6=√p^2+16

6=p+4

p=2

Answer 2

Answer:

The value of p = ±2√5

Step-by-step explanation:

If the two points A(x1,y1) and B(x2,y2)

then the distance between them denoted by AB and it is defined by

√[(X2-X1)^2+(Y2-Y1)^2]units