Question

If the distance between the points (4, k) and (1,0) is 5, then what can be the

possible values of k.​

Answer 1

Step-by-step explanation:

hope it will help u

possible values -4,4

Answer 2

Answer:

Let P(4,k) and B(1,0)

$5 = \sqrt{ {(1 - 4)}^{2} + {(0 - k)}^{2} }$

${(5)}^{2} = {(4)}^{2} + {( - k)}^{2}$

$25 = 16 - {k}^{2}$

$16 - 25 = - {k}^{2}$

$- 9 = {k}^{2}$

$\sqrt{9} = k$

$3 = k$

Hence, the value of k is 3.