Question

If the distance between the points (4,k) and (1,0) is 5, then what can be the possible value(s) of k

Answer 1

Answer:±4

Step-by-step explanation:

√(1-4)²+(0-k)²=5

=>(-3)²+(-k)²=25[squaring both sides]

=>k²+9=25

=>k²=16

=>k=±4

Answer 2

Answer:

Step-by-step explanation:

Here it is

By the distance formula d=√(x1-x2)+√(y1-y2)

Here d=5

Then

5=√(4-1)²+√(k-0)²

Which will give us

5=√9+√k²

So,

5=√(3+k)²

5=3+k

K=5-3=2

...hence the value of k is 2

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