Question

If the distance between the points (4,p) a
veen the points (4, p) and (1, 0) is 5 units, then value of pis :
(a) 4
(c)=4
(d) 5
(b) - 4​

Answer 1

Step-by-step explanation:

follow the above steps

Answer 2

The value of p is 4 and -4

Step-by-step explanation:

Given : The distance between (4,p) and (1,0) is 5 units

To find: The value of p

As we know the distance formula between two points

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where $(x_1,y_1) \text { and }(x_2,y_2)$ are the coordinated of points

As the distance between given two points is 5 unit

therefore

$5=\sqrt{(1-4)^2+(0-p)^2}$

Squaring both side and solving this we get '

$5^2=(\sqrt{(-3)^2+(-p)^2}) \\\\\Rightarrow 25= 9+p^2\\\\\Rightarrow 25-9=p^2\\\\\Rightarrow 16=p^2$

Therefore  p = 4 or p = -4

#Learn more

Find the value of P if the point A(0,2) is equidistant from (3,p) and (P,3)

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