if the distance between the points (4,p) and (1,0) is 5, then p is
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Answer:
V(4-1) 2+(P-o) 2 = 5
v3^2+P^2 = 5
squaring-> 9+ p^2 = 25
p^2=25-9=16
p=v16=4
p=4 is the answer
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