Question

If the distance between the points (4, p) and (1, 0) is 5, then p is equal to
(A) +4
(B) 4
(C) -4
(D) 0​

Answer 1

Answer:

here we apply distance formula that is

D=√[(x2-x1)^2 + (y2-y1)^2]

5=√[(1-4)^2 + (0-p)^2]

5= √[9+p^2]

25=9+p^2

25-9=p^2

16=p^2

4=p