Question

If the distance between the points (4, P) and (1, 0) is 5, then the
value of P is​

Answer 1

Answer:

$distance \: formula \: = \sqrt{} (x2 - x1) {}^{2} + (y2 - y1) {}^{2}$

Where, distance between the two points is 5 units, x2 = 1, x1 = 4, y2 = 0 and y1 = P

Substituting the values we get,

$5 \: = \sqrt{} (1 - 4) {}^{2} + (0 - p) {}^{2}$

$5 \: = \sqrt{} ( - 3) {}^{2} + ( - p) {}^{2}$

$5 \: = \sqrt{9 + p {}^{2} }$

Squaring both sides we get,

$(5) {}^{2} \: = (\sqrt{} 9 + p {}^{2} ) {}^{2}$

$25 \: = 9 + p {}^{2}$

$25 - 9 = p {}^{2}$

$16 = p {}^{2}$

$\sqrt{16 } = p$

$4 = p$

Answer 2

Answer:

p=4

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