If the distance between the points (4, p) and (1, 0) is 5, then the value of p is
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Answer:
The given points are (1,0) and (4,p)
d=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
⇒5=
(4−1)
2
+p
2
⇒25=(4−1)
2
+p
2
⇒25−9=p
2
⇒p
2
=16
⇒p=+4,−4
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