Question

If the distance between the points (4, p) and (1, 0) is 5 units, then the value of p is

Answer 1

Answer:

$\sqrt{(4 + 1) {}^{2} } +( 0 + p) {}^{2} = 5$

$\sqrt{5 {}^{2} + p {}^{2} } = 5$

$5 {}^{2} + p {}^{2} = 5 {}^{2}$

$p {}^{2} = 1$

$p = \sqrt{1}$

$p = 1or - 1$