Question

if the distance between the points (7, 4) and (3, y) is 4 units, find the value of y​

Answer 1

Answer:

The formula is Square root of (y2-y1)square+ (x2-x1)square

i.e square root of (y-4)square+(3-7)square=4

y^2+16-8y+16=16

y^2-8y+16=0

by finding roots we get the value of y is 4

Answer 2

Answer:

4

Step-by-step explanation:

Distance between any two points( say ( x₁ , y₁ ) and ( x₂ , y₂ ) ) is  given by $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Here, points are ( 7 , 4 ) and ( 3 , y ) and distance between them is 4 unit.

 Using distance formula :

⇒ √{ ( 7 - 3 )^2 + ( 4 - y )^2 } = 4

⇒  ( 7 - 3 )^2 + ( 4 - y )^2 = 4^2

⇒ 4^2 + ( 4 - y )^2 = 4^2

⇒ ( 4 - y )^2 = 0

⇒ 4 - y = 0

⇒ y = 4