If the distance between the points (8, p) and (4, 3) is 5 then value of p is 1 (a) 6 (b) 0 (c) both (a) and (b) (d) none of these
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Answer:
anwer is 0 and 6
Step-by-step explanation:
we know that
(distance)^2=(x2-x1)^2+ (y2-y1)
given ,
(x1,y1)=(8,4)
(x2,y2)=(p,3)
5^2=(4-8)^2 +(3-p)^2
25=16+9+p^2-6p
25=25+p^2-6p
p^2-6p=0
p(p-6)=0
p=0 and 6
I hope this helps you
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