Question

If the distance between the points (a,0) and (0,4) is 5 units,then the value of a is

Answer 1

heya dear your answer is here..
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(a-0)^2+(0-5)^2=5^2
a^2+25=25
a^2=0
a=0
hope it helps

Answer 2

pQ=√(x1-x2)^2+(y1-y2)^2
5=√(a-0)^2+(0-4)^2
5=√a^2+16
25=a^2+16
a^2=9
a=-+3
is your answer