Question

If the distance between the points A(x, -1) and B(3, 2) is 5 units, then find the value

of x.​

Answer 1

S O L U T I O N :

$\underline{\bf{Given\::}}$

If the distance between the points A(x, -1) & B(3,2) is 5 units.

$\underline{\bf{Explanation\::}}$

As we know that formula of the distance;

$\boxed{\bf{AB=\sqrt{(x_2 - x_1)^{2} + (y_2- y_1)^{2}}}}$

A/q

• x1 = x
• x2 = 3
• y1 = -1
• y2 = 2

$\mapsto\tt{5 = \sqrt{(3-x)^{2} + (2 +1)^{2}}}$

$\mapsto\tt{5 = \sqrt{(3-x)^{2} + (3)^{2}}}$

$\mapsto\tt{5 = 3-x + 3}$

$\mapsto\tt{5 = 6-x}$

$\mapsto\tt{5-6 = -x}$

$\mapsto\tt{\cancel{-}1 = \cancel{-}x}$

$\mapsto\bf{x= 1}$

Thus,

The value of x will be 1 .