if the distance between the points p(2,-3) and Q(x,-9) is √85 units then find the value of x
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Step-by-step explanation:
Distance = √(x2 - x1)^2 + (y2 - y1)^2
D = √85
p(2,-3) and Q(x,-9)
√85 = √(x - 2)^2 + (-9 + -3)
(a + b)^2 = a^2 + 2ab + b^2
√85 = √x^2 - 4x + 4 + -12
square both sides,
85 = x^2 - 4x - 8
x^2 - 4x - 93 = 0
Solve the quadratic equation the reach your answer.
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