Question

if the distance between the points P (4, 0) and Q (0, x) is 5 units,

then find the value of x​

Answer 1

Answer:

_____

Step-by-step explanation:

If the distance between P (4, 0) and Q(0, x) is 5 units, the value of x will be * 1 point.

Distance Formulae :

\sf{ \sqrt { { x_{2} - x_{1} } ^ 2 + {y_{2} - y_{1} } ^ 2 } }x2−x12+y2−y12

Substituting the given Values ,

\sf{ \sqrt { { 0 - 4 } ^ 2 + {x - 0 } ^ 2 } }0−42+x−02

=> \sf{ \sqrt { 16 + {x} ^ 2 } }16+x2

=> Squareing :

X^2 + 16 = 25

=> X ^ 2 = 9

=> X = 3 and -3

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Answer 2

Answer:

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