Question

If the distance between the points p(a,7) and q(1,3) is 5 units,then the value of a is

Answer 1

Answer:

$a=-\frac{4}{5}$

Step-by-step explanation:

Distance between points: $\frac{y_2-y_1}{x_2-x_1}$

Points given: $p(a,7)$ and $q(1,3)$

$\frac{3-7}{1-a}$

$\frac{3-7}{1-a}=\frac{-4}{1-a}$

$\frac{-4}{1-\frac{9}{5} }$

$\frac{-4}{1-1.8 }=5$

$a=-\frac{4}{5}$