Math, asked by Guru4633, 8 months ago

If the distance between the points p(a,7) and q(1,3) is 5 units,then the value of a is

Answers

Answered by budiharun
5

Answer:

a=-\frac{4}{5}

Step-by-step explanation:

Distance between points: \frac{y_2-y_1}{x_2-x_1}

Points given: p(a,7) and q(1,3)

\frac{3-7}{1-a}

\frac{3-7}{1-a}=\frac{-4}{1-a}

\frac{-4}{1-\frac{9}{5} }

\frac{-4}{1-1.8 }=5

a=-\frac{4}{5}

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