Question

If the distance between the points (x,2)
and (3,-6) is 10 units of what is the positi
-ve value of x​

Answer 1

Answer:

√[(x-3)²+(2+6)²]=10

(X-3)²+64=100;. (Squared on both sides

(x-3)²=36

x-3=6

X=9

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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