Question

if the distance between the third and fifteenth antinodes of a standing wave is 20 cm, wavelength of the wave is

Answer 1

Answer:

in between lies 15-3 that is 12 antinodes...and we know that per each wavelength lies two antinodes...so 6 wavelengths is 20 cm so wavelength is 10/3 cm mate... I hope this helps u mate

Answer 2

Given :

▪ Distance b/w third and fifteenth antinode = 20cm

To Find :

▪ Wavelength of the standing wave.

SoluTion :

☞ We know that, The distance b/w two successive nodes or antinodes is $\lambda$/2 and that b/w a node and nearest antinode is $\lambda$/4.

where,

$\lambda$ denotes wavelength of wave

→ Distance b/w antinodes = 20cm

→ (15-3)$\lambda$/2 = 20

→ 12$\lambda$/2 = 20

→ 12 × $\lambda$ = 40

→ $\lambda$=40/12

→ $\boxed{\bf{\lambda=3.33cm}}$