If the distance between two bodies is increased by 25% then the % change in the g force is.
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Dear student,
We know by the formula for gravitational forces that,
F = G m₁m₂/r²
or, F ∝ 1/r²
Consider the original distance to be r. Let the new distance be r' which can be denoted as per given as;
r' = 100% + 25%r
r' = 125%r
r' = 5/4 r
So, putting the given resultant value of r' in the formula, we obtain;
F ∝ 1/r²
F ∝ 1/ (5/4)²r
F ∝ 4²/ 5² r
F ∝ 16/25 r
F ∝ 16/25 × 100
F ∝ 16 × 4
F = 64%
So, % change in the the force is given by;
Δ F% = Foriginal - Fnew
Δ F% = 100 - 64
Δ F% = 36
Hence, % change in the the force is 36%.
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