Question

If the distance between two charged bodies is halved, the force between
them becomes :
(a) One-half (b) One-fourth (c) Double (d) Four times.​

Answer 1

Answer:

option d; four times.

Explanation:

Force is inversely proportional to the square of distance between the two charged bodies.

Answer 2

Answer:

(d) Four times.

Explanation: From the Coulomb's law,

F = kq1q2 / r^2 ( where k is the constant of proportionality)

If 'r' is halved, i.e. (r/2)^2

So, F' = kq1q2 / (r/2)^2

F' = 4 kq1q2 / r^2

$\Bold{\boxed{\mathbb{\orange{F'=4F}}}}$