Physics, asked by ak4192140, 1 year ago

If the distance between two charged bodies is halved, the force between
them becomes :
(a) One-half (b) One-fourth (c) Double (d) Four times.​

Answers

Answered by cyriacjoy001
5

Answer:

option d; four times.

Explanation:

Force is inversely proportional to the square of distance between the two charged bodies.

Answered by rishabh2328
2

Answer:

(d) Four times.

Explanation: From the Coulomb's law,

F = kq1q2 / r^2 ( where k is the constant of proportionality)

If 'r' is halved, i.e. (r/2)^2

So, F' = kq1q2 / (r/2)^2

F' = 4 kq1q2 / r^2

\Bold{\boxed{\mathbb{\orange{F'=4F}}}}

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