If the distance between two electric charges is doubled, how much will the force
exerting between them change ?
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F =kq1q2/r^2
F' = kq1q2/(2r)^2
=kq1q2/4r^2
=kq1q2/r^2 × 1/4
F' = F/4
therefore the force will change to F/4, that is decreases by 1/4th time.
hope it helped,
plzzz mark as brainliest....!!!!!!
F' = kq1q2/(2r)^2
=kq1q2/4r^2
=kq1q2/r^2 × 1/4
F' = F/4
therefore the force will change to F/4, that is decreases by 1/4th time.
hope it helped,
plzzz mark as brainliest....!!!!!!
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