if the distance between two equal point charges is doubled and their individual charges are also doubled,what would happen to the force between them
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Explanation:
▪️Initial force ⇒F=Kr2qq
▪️Final force ⇒F=K(2r)2(2q)(2q)=4r24Kqq=r2Kqq
▪️Thus, the force will remain unchanged.
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Answer:
double the number of induvidual charges
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