if the distance between two message body is reduced to half and mass of one of the bodies is also reduced to half what happens to the force of gravitation acting between them
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Answered by
2
Answer:
The force gets increased 2 times
Explanation: Formula of Gravitational Force = G1 = G * m1*m2/(r^2)
Let original masses and distance be m1 , m2 and r respectively.
New Variables:
m1/2
m2
r/2
New Force = G*m1*m2/2/((r/2)^2)
=G1 * 2
Therefore, the gravitational force between the two bodies gets increased by 2 times.
Answered by
2
Answer:
F = Gm₁m₂ / R²
Given ,
m₁ => m₁ / 2
R => R/2
F₂ = ( Gm₁m₂ / 2 ) / ( R/2 )²
= ( Gm₁m₂ / 2 ) / ( R² / 4 )
= 4Gm₁m₂ / R²
F₁ : F₂ = Gm₁m₂ / R² : 4Gm₁m₂ / R²
= 1 : 4
Hence , the gravitational force increases by 3 times its original value .
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