Question

If the distance between two objects decreases to 25%, then what % does the force of gravitation change. NO SPAM AND GET MARKED AS BRAINLIEST

Answer 1

Answer:

1600%

Explanation:

Distance between two objects decrease by 25%.

 Therefore, distance = (25/100) = ¼

  FG=1/r2               where FG is the force of gravitation and r is the distance between  

 two objects.

Therefore, the percentage by which force of gravitation decreases =(1/r2*100)% = (1/(1/4)2*100)% =(1/1/16*100)% = (1*16*100)% =1600%  

Answer 2

Answer:1500%

Explanation: Let distance b/w masses be r m. Masses be m1,m2.

F= Gm1m2/r^2.

In percent form we can write distance as 100%.

Therefore diff. in percent= 75%.

Therefore new distance = r-75%of r= 1/4r

Thus new force= Gm1m2/r^2/16=16Gm1m2/r^2

Therefore diff in force = Subtracting new eq from earlier one= Gm1m2×15/r^2

There % change= Gm1m2×15/r^2× r^2/Gm1m2×100%=1500%

Hope you understood. Please mark me as brainliest .