If the distance between two objects decreases to 25%, then to what % does the force of gravitation change
Answers
Answer:
1600%
Explanation:
Distance between two objects decrease by 25%.
Therefore, distance = (25/100) = ¼
FG=1/r2 where FG is the force of gravitation and r is the distance between
two objects.
Therefore, the percentage by which force of gravitation decreases =(1/r2*100)% = (1/(1/4)2*100)% =(1/1/16*100)% = (1*16*100)% =1600%
Answer:Answer:1500%
Explanation: Let distance b/w masses be r m. Masses be m1,m2.
F= Gm1m2/r^2.
In percent form we can write distance as 100%.
Therefore diff. in percent= 75%.
Therefore new distance = r-75%of r= 1/4r
Thus new force= Gm1m2/r^2/16=16Gm1m2/r^2
Therefore diff in force = Subtracting new eq from earlier one= Gm1m2×15/r^2
There % change= Gm1m2×15/r^2× r^2/Gm1m2×100%=1500%
Hope you understood. Please mark me as brainliest . This is the right answer . I'm dam sure