Question

if the distance between two point charges is increase by 3% then calculate the % decrease in the force between them​

Answer 1

Explanation:

Initial case when distance between charges is r the force can be determined as,

F

1

=

r

2

Kq

1

q

2

But when the radius between the charges increases that is when r→3r, New distance b/w charges, r

1

=3r, then force can be defined as,

F

1

=

(r

1

)

2

Kq

1

q

2

=

(3r)

2

Kq

1

q

2

=

9r

2

Kq

1

q

2

F

1

=

9

F

As the distance increases by 3 times the force reduces by 9 times.

Answer 2

if the distance between two point charges is increase by 3% then calculate the % decrease in the force between them