if the distance between two points (5,-2) and (1,a) is 5 find the value of a
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Answered by
0
Answer:
don't know sorry
Step-by-step explanation:
because I am a child of 3 class
Answered by
0
Step-by-step explanation:
⇒ The distance between two points P(x
1
,y
1
) and Q(x
2
,y
2
) is given by
PQ=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
here P(x
1
,y
2
)=P(5,−2)
& Q(x
2
,y
2
)=Q(1,a)
& PQ=5 units
i.e. 5=
(1−5)
2
+(a−(−2))
2
Taking square on both side we get,
∴25=(−4)
2
+(a+2)
2
∴25−16=(a+2)
2
∴(a+2)
2
=9
∴a
2
+4a+4=9
∴a
2
+4a−5=0
∴a
22
+5a−a−5=0
∴a(a+5)−1(a+5)=0
∴a(a+5)−1(a+5)=0
∴a−1=0 or a+5=0
a=1 or a=−5
→ The values of a will be 1 or −5
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