if the distance between two points A(1,1) B(x,1)=5units , then find the x
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AB² = (x1 - x2)² + (y1 - y2)²
(5)² = ( 1 - x )² + ( 1 - 1 )²
25 = 1 - 2x + x²
x² - 2x - 24 = 0
x² - (6 - 4 )x - 24 = 0
x² - 6x + 4x - 24 = 0
x (x - 6) + 4 (x - 6) = 0
(x + 4) (x - 6) = 0
Therefore x = -4 or x = 6
Distance can't be negative.
So x = 6
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(5)² = ( 1 - x )² + ( 1 - 1 )²
25 = 1 - 2x + x²
x² - 2x - 24 = 0
x² - (6 - 4 )x - 24 = 0
x² - 6x + 4x - 24 = 0
x (x - 6) + 4 (x - 6) = 0
(x + 4) (x - 6) = 0
Therefore x = -4 or x = 6
Distance can't be negative.
So x = 6
Hope you like it please mark as brainliest.
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I hope answer is helpful for you
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Bharatjaat:
thanks it very helpful to me
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