Question

If the distance between two points (a,2a) and A (4,3) is 25 units find the value of a

Answer 1

Answer:

A/Q

$distance = 5 \\ \sqrt{(a - 4) {}^{2} + (2a - 3) {}^{2} } =5 \\ \sqrt{ {a}^{2} - 8a + 16 + 4 {a}^{2} - 12a + 9 } = 5 \\ \sqrt{5 {a}^{2} - 20a + 25 } = 5 \\ 5( {a}^{2} - 4a + 5) = 25 \\ {a}^{2} - 4a + 5 = 5 \\ {a}^{2} - 4a = 0 \\ a(a - 4) = 0 \\ a = 0 \: \: or \: \: 4$