If the distance between two points (a cos 48,0) and (0,cos 36)is d then d^-a^=
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Given two points in 2-dimensions:
A = (a Cos 48° , 0) and B = (0, a Cos12°)
AB = d given
=> d² = (a cos 48° - 0)² + (0 - a Cos 12°)²
= a² * (Cos² 48° + Cos² 12°)
= a² * [(1 + cos 96°)/2 + (1 + cos 24°)/2 ]
= a² * [ 2 + 2 Cos 60° * Cos 36° ] /2
2 d² = a² * [2 + Cos 36°]
2 (d² - a²) = a² Cos 36°
=> d² - a² = a²/2 * Cos 36°
To find the value of Cos 36° :
A=36°Sin (2A) = Sin (180° - 3A) = Sin 3A2 Sin A Cos A = Sin A * (3 - 4 Sin² A)4 Sin² A + 2 Cos A - 3 = 04 Cos² A - 2 Cos A - 1 = 0Cos A = [1 + √5 ]/4Cos 36° = [1 + √5]/4
Step-by-step explanation:
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