Question

. If the distance between two points A (x , -1) , B ( 1 ,15) is 10. Find the value

of x.​

Answer 1

Answer:

Here is your answer

Distance formula = $\sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}$

A= $(x_{1} , y_{1})$ = $(x,-1})$

B= $(x_{2} , y_{2})$ = $(1,15)$

AB =$\sqrt{(x-1)^{2}+ (-1-15)^{2} }$

AB =$\sqrt{(x-1)^{2}+ (-16)^{2} }$

AB =$\sqrt{(x-1)^{2}+ 256} }$

Given AB=10

=> AB = $\sqrt{(x-1)^{2}+ 256} }$ = 10

on squaring

$(x-1)^{2}+ 256} } = 100$

$x^{2}-2x+ 1+156} }=0$

$x^{2}-2x+ 157} }=0$