if the distance between two points A(x, -1) b(1, 15) is 10 find the value of x.
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By distance formula
we have ,
√(x2 -x1 )^2 + (y2 -y1)^2 = AB
√ (1-x)^2 + {15-(-1)}^2 = 10
on squaring both sides
(1-x)^2 +(15+1)^2 = 100
1 + x^2 - 2x + 256 -100 = 0
x^2 -2x + 157 = 0
sry the question is wrong
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