if the distance between two points p,-5 and 2,7 is 13 units the value of
p is
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Answer:
Step-by-step explanation:
The distance formula between two points is = √(x₂ - x₁)² + (y₂ - y₁)²
(x₁ , x₂) ≡ (p , -5)
(y₁ , y₂) ≡ (2, 7)
The distance between two points is = 13
∴ √(2 - p)² + (7 - (-5))² = 13
Taking squares on both sides,
(2 - p)² + (7 + 5)² = 169
(2 - p)² = 169 - (12)²
(2 - p)² = 169 - 144
(2 - p)² = 25
taking square root on both sides,
2 - p = ± 25
p = 2 - 25 or p = 2 + 25
p = -23 or p = 27
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