Question

If the distance between two suspended masses 10kg each is tripled, the gravitational force of attraction between them is reduced by?

Answer 1

Answer:

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Answer 2

Answer:

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Explanation:

Let the distance apart the two masses = m.

From the equation F & M1 m2/ϒ2

F1 α 10 x 10/ϒ2 = F α 100/ ϒ2

F2 α 10 X 10/(3ϒ)2 => F2 α 100/9ϒ2

therefore F2/F1 = 100/9ϒ2/100/ϒ2 = 100/9ϒ2 ϒ2/100 = 1/9

Therefore F 2 : F 1 = 1 : 9

you would get a complete answer from this