if the distance between (x,-1) and (3,2) is 5 unit then find the value of x
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distance=√(2--1)^2+(3-x)^2
5=√(3)^2(3-x)^2
25=9+(3-x)^2
4=(3-x)
x=-1
5=√(3)^2(3-x)^2
25=9+(3-x)^2
4=(3-x)
x=-1
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