Question

if the distance between (x, 2), (8, 6) is 5 units then find x​

Answer 1

Answer:

i hope this answer helps you

Answer 2

Answer:

$distance \: formula \: = \sqrt{(x2 -x1)+(y2 - y1)}$

Given :

Point A coordinates : ( x, 2 )

Point B coordinates : ( 8 , 6 )

Distance between two points : 5 units

$\implies\;5=\sqrt{{(8 - x)}^{2}+{(6 - 2)}^{2}}$

$\implies\:{5}^{2}\;=\;{(8-x)}^{2}+{(6- x)}^{2}$

$\implies25=64+{x}^{2}-16x+16$

$\implies\:25\:=80+{x}^{2}-16x$

$\implies\:{x}^{2}-16x+55=0$

$\implies\;{x}^{2}-11x-5x+55=0$

$\implies\;x(x-11)-5(x-11)=0$

$\implies\;(x-5)(x-11)=0$

$\implies\red{\boxed{\:x\:=5}}$

Or

$\implies\orange{\boxed{\;x\;=11}}$