If the distance between (x,3),(4,5) is 2root5 then x=
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Given :-
- If the distance between (x,3),(4,5) is 2√5
To find :-
- Value of x
Solution :-
According to distance formula
→ AB = √(x2 - x1)² + (y2 - y1)²
Let,
- A = (x, 3)
- B = (4, 5)
According to the given condition
- AB = 2√5
→ AB = √(x2 - x1)² + (y2 - y1)²
→ 2√5 = √(4 - x)² + (5 - 3)²
→ 2√5 = √16 + x² - 8x + (2)²
→ 2√5 = √16 + x² - 8x + 4
→ 2√5 = √20 + x² - 8x
Squaring both side
→ 20 = 20 + x² - 8x
→ x² - 8x + 20 - 20 = 0
→ x² - 8x = 0
→ x(x - 8) = 0
Either
→ x = 0
Or
→ x - 8 = 0
→ x = 8
Hence,
- Value of x is 8
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