Question

if the distance covered by a body is a=at+1/2bt^2, then the acceleration of the body will be-
(a) a
(b) b
(c) 2b
(d) a+b

Answer 1

Answer:

2b

Explanation:

Given, position of the body x = at + bt^2

Velocity of a body is the rate of change of the position of the body.

So, v = dx/dt (differentiation of x w.r.t. t)

or, v = a + 2bt

Now, acceleration of the body is the rate of change of the velocity of the body.

So, a = dv/dt (differentiation of v w.r.t. t)

or, a = 2b

So, the acceleration of the body is 2b.