Physics, asked by Sathvikchv, 7 months ago

If the distance covered by a jogger is 2,541meters through the park and the time it took to cover that distance was 43.6 minutes, what was the speed of the jogger?
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Answered by hitankumar23
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Answer:

0.971 m/s

Explanation:

Distance covered (s) = 2541 m

Time (t) = 43.6 min = 2616 s

Speed = s/t

v = 2541/2616

v = 0.971 m/s or 1m/s

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