If the distance from the vertex to the centroid of an equilateral triangle is 6cm, what is the area (in cm2) of the triangle?
nichuZZZZ:
area of equ ∆=√3a×a÷4
Answers
Answered by
29
Equilateral triangle :
Side = a cm.
Altitude = √3/2 a cm.
Distance from a vertex to the Centroid = 2/3 * √3 /2 * a
= a/√3 cm
So given a/√3 = 6 cm.
a = 6 √3 cm
Area = √3/4 * a²
= √3/4 * (6√3)² = 27√3 cm²
Side = a cm.
Altitude = √3/2 a cm.
Distance from a vertex to the Centroid = 2/3 * √3 /2 * a
= a/√3 cm
So given a/√3 = 6 cm.
a = 6 √3 cm
Area = √3/4 * a²
= √3/4 * (6√3)² = 27√3 cm²
Answered by
24
distance from the vertex to the centroid = 6 cm
Let L is the sides of an equilateral triangle.
then, altitude = (√3/2)L
we know,
altitude is divide 2:1 ratio by centroid.
hence, distance from the vertex to the centroid = 2.Altitude/3 = 2(√3/2)L/3 = L/√3 = 6
L = 6√3 cm
now, area of triangle = √3/4(side length)²
= √3/4 × 6√3 × 6√3
= 27√3 cm²
Let L is the sides of an equilateral triangle.
then, altitude = (√3/2)L
we know,
altitude is divide 2:1 ratio by centroid.
hence, distance from the vertex to the centroid = 2.Altitude/3 = 2(√3/2)L/3 = L/√3 = 6
L = 6√3 cm
now, area of triangle = √3/4(side length)²
= √3/4 × 6√3 × 6√3
= 27√3 cm²
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