Question

If the distance of a particle at time t along straight line is given by y=A1+At+At^2,then acceleration of the particle will be

Answer 1

Just differentiate it twice........

Answer 2

Answer:2a

Explanation:

we know , v = dx/dt

a = dv/dt

x = ao + a1t + a2t2

v= dx/dt = 0 + a1 + 2a2t

a=dv/dt = d/dt (a1+2a2t)

=0+2a2

differntiation of constant is 0...

so accleration of particle = 2a2

option c is correct