Question

if the distance of a point from the base of a building is 15 m and angle of elevation to its top from that point is 60 degree. Then what is the height of the building?
a. 25m
b. 26m
c. 31m
d. 18m​

Answer 1

Answer- b. 26m

Step1- Let’s the height of the building be X meters. Now, Using Trigonometry we have:-

TanQ= X/15

Step2- Q=60

Tan60= X/15

Step3- “Square root of 3” = X/15

1.732 = X/15

Therefore, X = 1.732x15 = 25.980

On rounding off, we have X = 26m

Answer 2

Solution :-

From image let us assume that,

→ AB = Building with A as top and B as bottom

→ AC = 15 m = Distance of a point from the bottom of the building .

→ ∠ACB = 60° (given)

→ ∠ABC = 90°

So, in right angled ∆ABC,

→ tan 60° = AB/BC

→ √3 = AB/15

→ AB = 15√3 m

→ AB = 15 * 1.73

→ AB = 25.95

→ AB ≈ 26 m (Ans.) (B)

Hence, the height of the building is approx 26 m .

Learn more :-

The diagram shows two planks are slanted on a vertical wall.

Express cot x in terms of p.

https://brainly.in/question/24608435