Question

if the distance of the point (x, y) from the point (a, 0) be a + x. prove that y^2 = 4ax.

Answer 1

√(x-a)^2+(y-0)^2=a+x
(x-a)^2+y^2=(a+x)^2
y^2=(a+x)^2-(a-x)^2
y^2=4ax
hence proved