Question

If the distance of the point (X,y) from the points (1,2) and (-3,0) are equal then show that 2x+y+1=0​

Answer 1

Step-by-step explanation:

d=√((x2-x1)²+(y2-y1)²)

use this formula

(-3-x)^2 + (0-y)^2 = (1-x)^2 + (2-y)^2

9 + x^2 + 6x +y^2 = 1 + x^2 -2x +4 + y^2 -4y

9 + 6x = 1 - 2x +4 -4y

8x +4y +4 = 0

2x + y + 1 = 0