Question

If the distance time formula is given by s=2t³-15t²+36t+7, find the time when velocity become zero..

Answer 1

Answer:

By differentiation

v=ds/dt

6t^2-30t+36+0

when v=0

0=6t^2-30t+36

0=6(t^2-5t+6)

0=t^2-3t-2t+6

0=t(t-3)-2(t-3)

0=(t-3)(t-2)

t=3 or t=2

when time is on 2 sec and 3sec then velocity is zero....